Math Puzzle: the Missing Dollar

January 9th, 2009 | Categories: Logic, Math Puzzles

Here is a puzzle suggested by one of this blog’s readers, Sanket Totewar, which is a variant on the classic “where did that one go?” puzzle. Here goes.

Two women sell apples on a street corner. One sells 3 apples for 1$, the second sells 2 apples for 1$. Putting aside your microeconomics classes for a moment, image the following scenario. Each woman has 30 apples. If they were to sell their merchandise entirely, woman A would make 10$ while woman B would make 15$. Total: 25$. So far so good.

Instead, though, they decide to give their apples to a guy who sells 5 apples for 2$ (which is precisely what they would make if woman A would sell 3 apples and woman B 2 apples, a total of 5 apples). This guy sells the apples and gives the profits to the women.  However,  note that the 60 apples only made them 60/5*2=24$, one dollar less!

How can this be? Where did the dollar go?

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  1. MC Safety
    January 9th, 2009 at 12:55
    Reply | Quote | #1

    The discrepancy here lies in the ratio of apples the women have. If woman A possessed 36 apples (making $12), and woman B possessed 24 apples (making $12), they would make $24 total. But because they sell at different rates while starting with the same amount of apples, woman A will run out of apples first, leaving woman B with 10 apples to sell. If they sell separately (using only their own apples), they will make more money, but if their goal is to match 3 apples to 2 apples, they must split the remaining 10 apples into groups of 5 sold at $2 ($4 of profit) instead of groups of 2 sold at ($5 of profit), thus resulting in a $1 profit difference.

    Of course, in a realistic world, there are probably other advantages to having somebody else sell your apples in different quantities.

  2. January 13th, 2009 at 14:58
    Reply | Quote | #2

    Thanks for your insight, MC Safety.

    Looks like your puzzle was solved pretty fast, Sanket … I’d better hurry and put a new one up!

  3. adollar4u
    February 15th, 2009 at 01:57
    Reply | Quote | #3

    X=No of apples sold per dollar = 3A/D
    Y=No of apples sold per dollar = 2A/D
    Z= No of apples sold per dollar = 5A/2D or 2.5A/D

    (1) If they were to sell apples individually:

    Total profit = 30/X + 30/Y = 30:3A/D + 30:2A/D =25D

    (2) If they were to give all to Z to sell.

    Total profit = (30+30)/Z = 60:2.5 = 24D.

    Obviously it is more profitable to sell apples by each seller individually because apples were sold at a higher rate.